Merge pull request #2669 from bblommers/lambda-return-output-only

AWS Lambda - Return response only, and skip log/print statements
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Steve Pulec 2020-01-21 21:37:36 -06:00 committed by GitHub
commit 4335f1d3dd
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2 changed files with 8 additions and 35 deletions

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@ -58,8 +58,7 @@ def lambda_handler(event, context):
volume_id = event.get('volume_id')
vol = ec2.Volume(volume_id)
print('get volume details for %s\\nVolume - %s state=%s, size=%s' % (volume_id, volume_id, vol.state, vol.size))
return event
return {{'id': vol.id, 'state': vol.state, 'size': vol.size}}
""".format(
base_url="motoserver:5000"
if settings.TEST_SERVER_MODE
@ -181,27 +180,9 @@ if settings.TEST_SERVER_MODE:
Payload=json.dumps(in_data),
)
result["StatusCode"].should.equal(202)
msg = "get volume details for %s\nVolume - %s state=%s, size=%s\n%s" % (
vol.id,
vol.id,
vol.state,
vol.size,
json.dumps(in_data).replace(
" ", ""
), # Makes the tests pass as the result is missing the whitespace
)
log_result = base64.b64decode(result["LogResult"]).decode("utf-8")
# The Docker lambda invocation will return an additional '\n', so need to replace it:
log_result = log_result.replace("\n\n", "\n")
log_result.should.equal(msg)
payload = result["Payload"].read().decode("utf-8")
# The Docker lambda invocation will return an additional '\n', so need to replace it:
payload = payload.replace("\n\n", "\n")
payload.should.equal(msg)
actual_payload = json.loads(result["Payload"].read().decode("utf-8"))
expected_payload = {"id": vol.id, "state": vol.state, "size": vol.size}
actual_payload.should.equal(expected_payload)
@mock_logs